HC Verma Physics Part 2 Solutions for Chapter 42 Photo Electric Effect

5/21/2012

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Solution of HC Verma Concept of Physics -2 -Chapter 42 Photo Electric Effect

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15 Comments

divyansh meena

9/6/2013 05:18:54 am

why in q. no. 34 stopping potential is written as product of k with square of e then divided by 2d

pratik bafna

11/21/2013 04:53:09 pm

dear divyansh, at first stopping potential energy is equated to its kinetic energy. thereafter coulambian force ke^2/r^2 is equated to its centripetal accelaration . the mysterious factor 2 in the denominator is coming from the kinetic energy of an ejected electron which is not explained clearly in the solution.

Sankalp

12/9/2013 06:13:03 pm

sir please explain sol. of 7th ques...after force = power/c

Sankalp

12/9/2013 06:24:52 pm

sir in quest. 8 why force = 2* (power/c) rather than f= power/c

theyatin

12/10/2013 01:00:56 pm

Rate of change of momentum = Power/C
F*d= W
W/T=P
F*D/T=P
F*V=p
F=P/V
now this if force for every foton but there is another foton ast same distance from horicontal axis of lens which needs to be calculated.
thus we use 2F

vipul

10/7/2019 11:21:51 pm

Change in momentum is twice of initial momentum

theyatin

12/10/2013 01:05:07 pm

dear,
here 70% are absorbed
and 30% are reflected
hence we have 7/10 and 3/10
but as explained in 8th Q we can have two photons for same distance from center thus multiply by two.

Sankalp

12/12/2013 02:42:47 am

Thanks alot yatin sir for ur response... but sir i hav still not understood this photons and reflection concept..

gopal

3/7/2014 10:42:23 am

sir, i am confused in q-2(objective1). pls give explanation of all the options whether it is correct or not.

daniel

9/10/2014 02:46:51 am

hai

sreejita chakrabarti link

10/22/2014 03:40:17 am

Ayush link

10/23/2014 01:22:03 pm

Sir in ques. 10, area if sphere is taken to be pi r^2 instead of 4pi r^2....
Why is that so?

kunal

1/5/2016 09:59:24 pm

Cause i think as the appreture is large so instead of covering whole sphere it will only cover a specific curve(circle)

Rohit

6/11/2015 07:39:33 pm

In ques 7th the force due to reflected light is taken in consideration but in 8th it is not. Whats the reason ??

ray

10/23/2015 10:43:55 am

sir,
I think in q.31 electric field due to charged plate should be (Q/2*A*E)
not (Q/A*E). As it is field due to a single charged plate and not charged surface or two charged plates. Please, remove my confusion ,if any????

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