Solution of HC Verma : Concept of Physics – I : Chapter 9 Centre of Mass Linear Momentum Collision5/21/2012 Solution of HC Verma : Concept of Physics – I : Chapter 9 Centre of Mass Linear Momentum Collision For any problem in solving any question leave us a comment our expert will give your answer within 24 hrs.
304 Comments
9/14/2012 07:09:04 pm
This is a good process to improve my knowledge about problems of physics
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sassad
7/25/2015 02:25:43 pm
bhai tu chup bait
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advait patole
10/18/2012 03:26:50 am
not understood solution of center of mass 22question {exercises}
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Admin
10/18/2012 11:42:15 am
we know that explosion of block is an internal force. there is no external force acting on the body. so here we are using the concept of conservation of momentum which means that momentum before explosion and after explosion remains same. as given in the question that the body was at rest, so the momentum was zero.
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Pragyan
11/13/2014 01:07:46 pm
can you explain me how to calculate time of flight in question no. 55 of chapter 9 (exercises) of hc verma
Aman
10/29/2012 10:51:41 pm
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anisha
9/22/2015 12:18:59 am
Conserve the momentum and equate it of both the balls😊
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Admin
11/3/2012 03:08:24 pm
This is attempt to provide free education to children who are preparing for engineering entrance examination.
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Avinash
11/4/2012 12:20:52 pm
Sir, this site really proved to be very helpful for me..!!! Very nice solutions and well explained too..!!! Please do something for the short answer type questions of HCV..!! thank you.
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Admin
11/4/2012 07:55:50 pm
Dear Avinash you can also ask "short answer type question" in which you are facing problem.
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Karan Muvvala
11/7/2012 07:47:28 pm
sir can u explain me q 24 and how to find average force delivered
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Admin
11/7/2012 09:28:01 pm
Dear Karan,
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Rajat
11/15/2012 08:42:43 pm
pls explain...
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Rachana
7/13/2017 07:12:33 am
Bullet stokes the block with a speed 500m/s.and the bullet comes out of the block with the speed 100m/s.Let us take that this happens in a very short time and conserve momentum,
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Admin
11/16/2012 11:50:05 am
Your answer will be uploaded on 18th Nov.
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Rajat
11/16/2012 02:13:51 pm
Its absolutely ok! I'll wait for the answer...
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Admin
11/17/2012 06:05:48 pm
Dear Rajat,
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arjun
5/27/2013 11:13:21 pm
sir pls explain why enegry conservation eq give wrong ans in this question i.e
Mainak Pal
11/26/2015 10:35:10 am
but what about the frictional force???
Rajat
11/17/2012 08:36:58 pm
Got it ! thank you..
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Admin
11/18/2012 12:00:58 am
Dear Rajat,
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Rajat
11/18/2012 12:37:28 am
Sir you explain very well...now i understood the real meaning of angular freq ! Thank you for the help....
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m k rao
11/18/2012 07:43:37 pm
sir can u explain q36 step 11 and q37
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Admin
11/18/2012 08:44:25 pm
Dear M K Rao,
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Admin
11/19/2012 07:33:57 pm
Dear M K Rao,
KUNAL
5/9/2015 09:34:09 pm
BUT IN A I M GETTIN 0 AS TOTAL LOSS
hahaha
9/10/2016 03:59:20 am
(v1 – v2) + ℓ (a1 – u2) = 0 ℓa = v2 – v1 ..(2)
Karan Muvvala
11/20/2012 01:40:00 am
in question 55 i did not understand the last step
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Admin
11/20/2012 08:11:29 pm
Dear Karan,
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Raman
11/24/2012 05:19:51 pm
sir please explain me the 59th question ,i wanted to know the equation v1-v2=(u1-v2)is the eqn for coefficient of restituion
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Admin
11/25/2012 09:11:13 am
Dear Raman,
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Admin
11/25/2012 09:16:54 am
Dear Raman,
Raman
12/1/2012 11:46:25 pm
Please explain me the 3rd and 16th question of chapter 10 ie rotation of HC Verma.Just getting a bit confused
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Admin
12/2/2012 10:58:45 am
Dear Raman,
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Raman
12/1/2012 11:48:22 pm
And sir I'am just not arriving at the right answer so please do solve the complete 16 question or atleast do write the basic integrating equation
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Raman
12/2/2012 12:18:08 pm
Sir the 21st question is really getting me confused.How could the normal force of the block or any of the components of it or even weight can produce torque about the centre of the block.I 've downloaded the sol of HC verma of all chapters and the solution given for this is totally absurd.Please reply at the earliest ....
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Raman
12/2/2012 12:22:16 pm
Sir for the 3rd question of rotation ,i know that the area under the curve gives the value of the prod of quantities taken but here we need ang velocity and ang acceleration is given which is not constant and then graph for velocit would be curved and in the sol it is given a straight line.Getting totally confused seeing the solutions
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Raman
12/2/2012 12:40:06 pm
Sir sorry about so many doubts but you are really helping me a lot,I'am studying in 10th and just wanted to complete the important chapters of HCV ,so u are my only teacher at the moment.
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Raman
12/2/2012 12:49:09 pm
Sorry sir but i've got the answer of ques 23 by that method ,i just took the wrong Moment of inertia .......Please do reply for the other questions
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Admin
12/3/2012 10:03:56 am
# Solution of question number 21
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Raman
12/3/2012 11:55:28 am
sir in your explaination for question 21 the thing I'am not understanding is that how can mgsin0(0 is for theta) produce a torque because it is like mgcos0 is a component of weight so it will also pass through the centre ,is there some reason because of which sine component of weight shifts and is not acting on the centre.If there is some reason sir please explain me...waiting for your answer
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Admin
12/4/2012 09:58:46 am
Dear Raman,
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Admin
12/4/2012 10:01:02 am
Dear Raman,
Raman
12/3/2012 07:06:09 pm
Sir please explain the 44 question of rotation.The diagram in the solutions given is totally confusing.If possible please explain the what forces and how are they mentioned in context of the diagram..
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Raman
12/3/2012 07:07:43 pm
Sir please explain the 44 question of rotation.The diagram in the solutions given is totally confusing.If possible please explain what forces will act and how are they mentioned in context of the diagram..
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Admin
12/4/2012 10:19:31 am
Dear Raman,
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Raman
12/3/2012 08:59:49 pm
Sir please explain the in depth concept of questions 56,57,58 of rotation that is how does torque remains 0 and what is the basic logic behind these type of questions.
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Admin
12/4/2012 10:39:42 am
Dear Raman,
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Raman
12/4/2012 01:01:10 am
sir explain me the questions 59 to 63 of rotation.I'am getting confused about when to take linear momentum and ang momentum and sometimes simultaneously linear and ang mom and other such things.Please explain the basic concept behind all this so that my basics get really clear about ang momentum and i can deal with such problems
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Admin
12/5/2012 10:25:27 am
Dear Raman,
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Raman
12/4/2012 11:33:27 am
thanks a lot sir about the 21st question,i just didn't read the ques carefully which mentioned that velocity is uniform ie a=0 and therefore friction balances mgsin0.
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rohan kapadnis
12/5/2012 12:13:08 am
sir can u plz explain me the 11th and 12th question of centre of mass
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Admin
12/5/2012 08:32:58 pm
Dear Rohan,
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Raman
12/6/2012 12:08:47 am
Sir please i have doubts in the 85th and 86th questions.Sir in the 85th question ho wto take the directions of the linear and angular momentum ,i mean that when will they be opposite to each other because in ques 86th thefinal linear and ang momentum being opp to each other are taken as opposite.I just didnt understand hpw will one decide the direction .Sir please explain me the 85th question in detail,i got to the answer but now some things are confusing me and please write the full equation.
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VIVEK
12/25/2012 03:48:37 pm
sir please explain ques-29 chap-9(exercise)
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admin
12/25/2012 08:40:08 pm
Dear Vivek,
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devesh yadav
12/25/2012 04:55:22 pm
Sir please explain me the question no 44 from chapter 9...
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admin
12/25/2012 08:17:52 pm
Dear Devesh,
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Kushal
12/21/2013 01:36:09 am
why u are taking y = l sinθ ... because in soln there is y= - lsinθ
rahul
4/2/2015 06:22:08 pm
Why alpha= 90-thita
Rajat
1/23/2013 03:01:07 am
A man starts walking on wedge which is placed on smooth surface. When the man reaches the top most position we have to find the displacement of wedge wrt earth.
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Admin
1/23/2013 06:34:43 pm
Dear Rajat,
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shalu
1/24/2013 10:52:52 pm
sir please explain me qestion no 54 and 59 and center of mass of continous bodies
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Admin
1/25/2013 10:56:29 pm
Dear Shalu,
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Admin
1/26/2013 11:42:33 am
Dear Shalu,
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yash
1/25/2013 01:22:16 pm
sir i have doubt in q25.. that how the impulsive forces are taken as zero after long interval of time..
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Admin
1/25/2013 11:01:05 pm
Dear Yash,
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pari
2/6/2013 10:13:47 pm
mass=densty *volume
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Admin
2/7/2013 07:36:19 pm
Dear Pari,
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ruby
2/6/2013 10:24:30 pm
examp : 2 ,18
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Admin
2/7/2013 07:50:46 pm
Dear Ruby,
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Admin
2/7/2013 08:04:16 pm
Dear Ruby,
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ruby
2/7/2013 12:23:32 pm
plz expln Q:7 i dnt undrstnd
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Admin
2/7/2013 08:24:41 pm
Dear Ruby,
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M.y
2/7/2013 12:37:35 pm
Q 11 of excrse
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Admin
2/7/2013 08:26:53 pm
Dear M.y,
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Prateek
2/8/2013 12:52:37 am
sir..can u explain ques 27 of chapter 9..i didnt quite get it..then after 1st bullet is fired the car already attains sum velocity...then how to conserve momentum afterwards..when second bullet is fired..
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Admin
2/8/2013 05:27:02 pm
Dear Prateek,
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Prateek
2/8/2013 01:00:43 am
Sir..in the solution of ques 28 above..they havent considered the velocity which the car attains after first person jumps in momentum conservation..they have solved two cases differently..and then took out the rsultant velocity..Why is the velocit initially attained by car not considered in momentum conservation..????Pllzz do explian sir....Thank you
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Admin
2/8/2013 05:28:49 pm
same as above
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Prateek
2/9/2013 01:26:20 am
Thanku sir..One last thing i wanna ask is..are the ans of ques 46 and 56 (b) wrong..??
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Prateek
2/9/2013 01:29:42 am
Sorry sir understud the why it is 2l in 56th..please tell about ques 46..Thank You sir..u are a saviour..:)
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Admin
2/10/2013 08:40:47 pm
Dear Prateek,
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Rk
2/11/2013 04:43:01 am
plz explne example 6
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Admin
2/11/2013 08:50:43 pm
Dear RK,
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ruby
2/12/2013 12:35:16 am
in Q 27 we hv given mass=50m bt hw obtn 49m and 48m
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Admin
2/12/2013 08:47:30 pm
Dear Ruby,
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Prateek
2/12/2013 02:37:17 pm
Sir..I dont know the fundas behind variable mass system involving 'chain problems' etc that involves integration sumtimes..can u suggest me any book..or any link..or any video..i just need to see one or two examples..they will be handful..:)
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Admin
2/12/2013 09:08:53 pm
Dear Prateek,
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Asnaf Khan
2/15/2013 05:28:18 pm
Sir, would you please explain Q. 19 ... i could'nt get the part where you find time difference.
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Admin
2/15/2013 09:05:56 pm
Dear Asnaf,
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Rajat
2/22/2013 03:25:09 am
In page number 152 question 9 there is a block of mass m on top of block of mass 10m. We have to find the distance moved by bigger block at instant when smaller block reaches the ground. I cannot understand how it is solved in the book...is there another method also so i can understand it? Like taking accelerations , conserving momentum and all..
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Admin
2/22/2013 09:56:29 pm
The doubt solving service for HC verma has been disabled for few days. We are very happy with the faith the students have shown in our service. We are hiring more and more teachers and upgrading our features like audio video techniques to solve your doubts.
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najeeb mannan
2/24/2013 01:36:21 pm
sir, can you explain elastic and inelastic collisions, please?
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palki
3/1/2013 01:51:15 am
i want the worked out problems from work power and energy of hc verma
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theyatin
4/6/2013 12:39:58 am
dear palki. . .
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arjun
5/28/2013 12:41:57 am
sir pls explain q no 43 &
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arjun
5/30/2013 06:00:48 pm
sir thank u to support a lot.
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theyatin
5/30/2013 06:51:33 pm
dear,
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ram
5/30/2013 06:29:27 pm
why in que no 42 the momentum conservation is applied (as friction is present as external force)
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theyatin
5/30/2013 11:32:42 pm
dear,
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theyatin
5/30/2013 11:35:12 pm
dear ram,
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theyatin
5/30/2013 11:43:53 pm
dear,
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mvs saketh
6/13/2013 08:38:35 pm
Admin,, in question no,. 13.. Mr Verma and Mr Mathur are part of the system,, so if they apply any force on boat which is also a part of the system,, the cm position should not change as they are internal forces,, then how did it change ???
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Admin
6/13/2013 10:21:15 pm
Dear saketh,
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Mvs saketh
6/13/2013 11:31:17 pm
i got the answer myself,, thankyou
Vaibhav Arya
7/12/2013 01:34:18 pm
sir, pls explain q no 49 & 50
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theyatin
7/12/2013 04:31:41 pm
dear,
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theyatin
7/12/2013 04:38:30 pm
dear,
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Karthik
7/24/2013 01:46:34 am
Respected sir,
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theyatin
7/25/2013 01:00:11 am
dear,
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Akhil Krishna
7/26/2013 01:58:49 am
Please explain exercise question no. 29 !!
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theyatin
7/31/2013 02:21:00 am
dear,
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Akhil Krishna
7/26/2013 02:22:10 am
questn no 38 too !!
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theyatin
7/31/2013 02:23:52 am
dear,
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himani
7/30/2013 12:50:51 pm
sir plz explain ques 45 chapter 9
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Abhay Verma
8/1/2013 04:05:28 am
sir please explain the Q.6 , Q.17 of short anwers questions of Chapter 9 Centre of Mass,Linear momentum,collison
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theyatin
8/3/2013 03:16:04 am
dear,
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theyatin
8/3/2013 03:17:48 am
dear,
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Rachana
7/12/2017 09:08:39 am
Since, the car is accelerating the change in momentum would not be constant.And we can't conserve momentum.Here,the external force is the pseudo force.
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Rana
8/21/2013 02:57:41 am
hello..
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theyatin
8/23/2013 03:27:28 am
dear,
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ishani
8/30/2013 02:28:54 am
in question no. 2 why thita is taken as origin pls explain
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theyatin
8/30/2013 03:08:29 am
dear
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ishani
8/31/2013 01:37:43 am
why in question no 4 x1 is taken as R?
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theyatin
9/1/2013 01:11:46 am
dear,
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ISHANI
9/1/2013 02:33:27 am
SIR , WHY IN QUESTION NO4 (x1) is taken as R?
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theyatin
9/4/2013 04:02:36 am
dear,
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Shraddha Sonkar
9/11/2013 01:22:52 am
Question number 64(page-164).
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theyatin
9/11/2013 02:42:58 am
dear,
Reply
THE STUDIOUS
9/11/2013 10:58:48 am
please explain question number 56 of the chapter centre of mass,linear momentum and collision in HC verma.
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theyatin
9/14/2013 03:29:20 am
dear,
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the iit man
9/17/2013 10:08:53 pm
sir in your 54 ques you have done a major mistake in the problem solving part
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theyatin
9/22/2013 02:08:19 am
dear,
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Anurag Mittal
9/20/2013 03:25:37 am
i am unable to understand q-11
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theyatin
9/22/2013 02:22:44 am
dear,
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Anurag Mittal
9/20/2013 03:29:38 am
in hcv q-3 answer behind is given 22/35 whereas ur answer is 11/35 which one is correct
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thyeatin
9/22/2013 02:24:49 am
dear,
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raju
9/27/2013 08:05:55 pm
sir, i can't understand the 56th problem of center of mass??
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theyatin
9/29/2013 04:26:48 am
dear,
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satyam
10/7/2013 02:29:25 am
sir can u please give me tips to improve my physics
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theyatin
10/8/2013 05:11:41 pm
dear,
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Harshit Aggarwal
10/16/2013 02:36:21 am
how we have to find the distance of mass of semicircular plate from its centre.
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theyatin
10/16/2013 03:37:57 am
dear,
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Harshit aggarwal
10/16/2013 10:54:15 pm
yes I am talking about center of mass
Abhay Verma
10/16/2013 05:30:20 am
sir please explain question 60
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Aymanzoor
10/19/2013 08:09:04 pm
Sir
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theyatin
10/23/2013 02:31:49 am
dear,
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Aymanzoor
10/26/2013 12:04:16 am
but how can KE be negative
theyatin
10/26/2013 02:19:05 am
dear,
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Aymanzoor
10/20/2013 02:54:58 pm
Sir
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theyatin
10/26/2013 02:40:23 am
dear,
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Aymanzoor
10/20/2013 05:00:00 pm
sir the answer given in q58 pt b is written as 25m in verma
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theyatin
10/26/2013 02:47:14 am
dear,
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divyam bhaskar
11/11/2013 11:31:44 am
Sir plz explain q.no. 19
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theyatin
11/18/2013 09:56:28 pm
dear,
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Arpit
11/18/2013 09:21:25 am
sir can plz explain why in q.no.43 velocity of approach is taken as v whreas it is u
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Arpit
11/18/2013 09:22:54 am
i am talking about the lesson centre of mass
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theyatin
11/18/2013 10:00:32 pm
dear,
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Arpit
11/23/2013 08:43:08 am
oh!!!thank you sir
saloni kumari
11/18/2013 03:34:49 pm
sir plz tell me question no 56
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theyatin
11/18/2013 10:02:41 pm
dear,
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ankit rai
11/19/2013 03:24:48 pm
thanks sir
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theyatin
11/19/2013 04:47:11 pm
dear,
Reply
ankit rai
11/19/2013 09:36:53 pm
please explain solution of the question no.14 chapter-9 exercise?
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theyatin
11/22/2013 02:10:38 am
dear,
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ankit rai
11/19/2013 09:43:49 pm
sir ,please explain the answer of question -6 MCQ, CHAPTER -9
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theyatin
11/22/2013 02:05:54 am
dear,
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shivam
11/28/2013 09:10:01 am
please explain q.no. 41 &42
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theyatin
11/29/2013 01:27:03 am
dear,
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theyatin
11/29/2013 01:47:31 am
dear,
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shubh
11/28/2013 02:46:14 pm
In finding resultant acc. Of small mass m w.r.t wedge. Why a2 is in left dir. Can we solve it using enegy conservation law but l m unable to get relation beteen velocities of mass and wedge !!!
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theyatin
11/29/2013 02:04:59 am
dear,
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shubh
11/28/2013 02:50:15 pm
Sorry I forgot to mention Q no. Its 60
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shivam
11/29/2013 11:06:59 pm
sir
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theyatin
11/30/2013 02:04:26 am
dear,
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shubhu
12/5/2013 12:54:16 pm
Just use the relation of K.E and linear momentum i.e K=p²/2m and just equate as required!!!
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Neeraj
12/7/2013 12:15:33 am
In HCV the answer for q46 is given as 6.1cm but here it is given as 4.5cm which one is correct?
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anushya
12/7/2013 07:08:57 pm
can u please explain q10 of centre of mass.
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varun
12/7/2013 07:27:31 pm
even i havent understood q10,sir can you please explain?
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shubhu
12/11/2013 12:51:39 am
Due to absence of any net attraction force on liquid it will acquire spherical shape due to surface tension. And since there is no external force c.m will not chage
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Shreyas
12/11/2013 12:22:28 am
sir....in question 53........how is it possible that the pillow and man reach reach at the same initial position.......since there is no gravity ....how can the man come down again?
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theyatin
12/22/2013 12:48:04 am
dear,
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Shreyas
12/22/2013 02:06:06 pm
but sir theres not even internal forces between them which will bring them together......i dont think that the man will come down.......and also theres no specification that the speed of pillow is relative to the man.............
Shreyas
12/22/2013 02:07:10 pm
but sir there's not even internal forces between them which will bring them together......i dont think that the man will come down.......and also there's no specification that the speed of pillow is relative to the man.............
Shreyas
12/22/2013 02:07:51 pm
but sir there's not even internal forces between them which will bring them together......i dont think that the man will come down.......and also there's no specification that the speed of pillow is relative to the man.............
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theyatin
12/24/2013 11:13:50 pm
dear,
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Shreyas
12/25/2013 12:33:59 am
sir .....by applying momentum conservation of (man +pillow)system:
Shreyas
12/25/2013 12:36:57 am
not m/sec......its ft/sec.......
theyatin
12/27/2013 03:34:24 am
dear,
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Pratik
12/24/2013 01:22:25 pm
Sir in example 17 & 24 why we don't consider gravitational force as external force & in presensence of an external force how can we conserve momentum
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theyatin
12/24/2013 10:48:40 pm
dear,
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Shreyas
12/25/2013 01:06:08 am
in example 17........the (man+earth) is the system.......therefore gravitational force acts as an internal force between them...
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Krishna
9/29/2016 01:31:57 pm
Hi,
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Pratik
12/25/2013 11:02:15 pm
But we take hailstone +earth + roof as a system don't we have to calculate earth in momentum conservation as the earth has a very large mass??
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theyatin
12/27/2013 03:01:33 am
dear roof is in contact with earth so eventually it is part of earth
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Shreyas
12/26/2013 12:14:06 am
observer is on the earth =>earth is at rest with respect to observer
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theyatin
12/27/2013 02:48:55 am
dear,
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aditya sahu
12/31/2013 04:05:31 pm
Please help me I don't know how to do hcv question number 59 from rotational motion page number 199
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theyatin
12/31/2013 10:53:38 pm
dear,
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Shreyas
12/31/2013 11:58:30 pm
a)change in linear momentum(of the rod) = impulse(Chapter 9)
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vishwa
1/1/2014 07:16:05 pm
the explanation you gave in ques 23 is not understood to me..please explain in another way. i interpreted the solution that as the system is isolated the mass lossed by astrounauts will remain in spaceship so there will be no change og velocity. Is it correct?
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theyatin
1/3/2014 01:30:20 am
dear,
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Shreyas
1/1/2014 08:15:42 pm
yes it is correct........i too had faced problems in this particular question......the mass lost by the astronauts are converted to some equivalent form of energy(by doing exercise-the energy required to do the exercise is produced by the fats stored in astronauts-making them to loss mass) .....so this energy can be again converted to form equivalent amount of mass....E=mc^2 .........and i m also a student....sir if m wrong anywhere please point it out....listening to others doubts really helps a lot
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theyatin
1/3/2014 01:21:15 am
dear shreyas i am glad that you people are helping each other but you need to answer the question in the reply option otherwise person asking question may not know that you have answered.
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Mohak
1/13/2014 03:59:40 pm
Sir in que 57 why we take dx/dt as dv and what is the physical significant of this?
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Shreyas
1/13/2014 08:49:30 pm
v = dx/ dt
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theyatin
1/14/2014 01:49:01 pm
dear derivative of distance w.r.t to time means change of distance w.r.t. time that is velocity or motion
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Mohak
1/14/2014 02:37:46 pm
But sir we have considered that dx is the elemental length of mass dm then why we consider it as a distance...
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theyatin
1/20/2014 01:42:35 pm
dear,
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Mohak
1/17/2014 04:48:41 pm
Sir I haven't got my answer so far...sorry!!
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Jay
1/20/2014 12:15:03 am
Sir I got same question as mohak
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theyatin
1/20/2014 01:43:12 pm
dear,
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Mohak
1/21/2014 10:23:13 pm
Sir how can we solve que 60 using energy conservation?
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theyatin
1/23/2014 01:04:09 am
dear, please show me how are you proposing to attempt this question?? this way
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Shreyas
1/23/2014 01:23:28 am
sir in SHM page no.253 ......Question no.19,20......plz explain how to get the forces exerted by spring A & B ...especially in Q.20...plz help
theyatin
2/19/2014 01:08:38 am
dear,
Mohak
1/23/2014 12:47:43 pm
mgh= 1/2mv^2 + 1/2MV^2
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theyatin
2/19/2014 12:57:03 am
but dear it is not required answer.
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abhinav
2/18/2014 09:42:08 pm
sir in q57 we took dx as the smallest possible elemental length..then when we found out the opposing force by the ground for its momentum to be zero..but isnt it for the small element only..
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theyatin
2/19/2014 01:05:20 am
dear,
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abhinav
2/19/2014 04:00:49 pm
sir mujhe ye smajh nhi aaya ki pehle unhone dx length ka momentum calculate kra fir jab rate of change of momentum nikala tab wo dx/dt kiski velocity represent kr rha hai...
sachin jha
3/6/2014 11:23:49 am
sir what is thermodynamics with its application and its proof?
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Admin
3/6/2014 03:58:42 pm
Please wait. Yatin sir will resume work within 2-3 days.
Reply
Aditya
3/7/2014 02:41:53 am
In Q 43
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theyatin
3/19/2014 01:37:35 am
dear,
Reply
3/8/2014 09:16:40 pm
sir I am unable to know step m1x1=m2x2 in question no. 49 0f centre of mass.
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theyatin
3/19/2014 01:28:09 am
dear,
Reply
3/27/2014 01:07:04 am
Sir,but I want to know that why in a spring system this mass is inversely proportional to the distance? Sir, is it by the application of centre of mass in a system?
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theyatin
3/28/2014 11:33:09 pm
dear,
Reply
theyatin
4/1/2014 04:35:42 am
dear,
Reply
4/1/2014 03:43:05 pm
sir I have posted my doubts in next chapter rotational mechanics. please sir check them out.
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pavandeep kaur
4/10/2014 10:50:20 pm
can u pls explain the 49 th sum of collision
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sx
4/21/2014 05:18:11 pm
y du v need 2 tke d sum of velocities in 27q plz exp in detail!!!!
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xwedeerf
4/21/2014 10:59:12 pm
suggest me sum other method 2 solve d 27q plz!!!!!!
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niti n
4/21/2014 11:01:06 pm
suggest me sum other method 2 solve d 27q plz!!!!!!
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niti n
4/24/2014 03:11:27 pm
hi,swadhin....thx but cud u explain dat further???
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4/24/2014 03:32:32 pm
Hey it is the eeuation of motion in circular path see chapter circular motion it is there.
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niti n
4/24/2014 03:14:16 pm
has 'ny1 got d alternate method 2 solve d 49Q....plz reply!!!!
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ravi kumar
5/29/2014 02:01:04 am
sir explain about collision
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mirjaik
5/31/2014 12:29:33 am
an instance of one moving object or person striking violently against another
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admin
6/22/2014 01:47:20 pm
Dear Students,
Reply
shubham
7/6/2014 02:36:17 pm
i didnt get chapter 9 exercise que nos 35,51,48,60,61 please replay fast...
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Sumedha Ghoshal
8/9/2014 12:51:20 am
sir cld u xplain me ques 25 and 33.
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Sumedha Ghoshal
8/9/2014 12:58:10 am
sir pleas explain example 19 of chapter 9 the line "As the centre of mass is at rest in this frame the blocks move in opposite directions and come to intantaneous rest at some instant.The extension of the spring will be max at this instant." PLEASE do reply .
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Sumedha Ghoshal
8/9/2014 03:28:12 am
the sums having two bodies connected by a spring are creating problem for me.i couldnt understd ques 49 soln. PLEASE HELP !!!!
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Sumedha Ghoshal
8/14/2014 09:08:15 pm
u hav promised to deliver answer within 24 hrs but i have waited for
Reply
9/1/2014 01:51:13 am
this is so good thank you for the solutions this actually increases my knowledge
Reply
Vivek Om
9/11/2014 02:28:20 am
this is to all if anyone knows solution of 4th que. Pls leave a reply..
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Sashank
9/11/2014 07:50:16 pm
Sir thanks a lot. This has helped me a lot. I have a doubt in 60th question. Shouldn't acceleration in horizontal direction be 0. You guys seemed to have conserved acceleration rather than velocity(or maybe I understood it wrong, I have not quite got how you got the acceleration of the big block) if we take the horizontal plane at an angle Alfa to the incline, and the vertical plane 90- Alfa the answer will vary greatly. Because then horizontal momentum should be zero. So velocity of big block w.r.t small block horizontal velocity is found. And so on.
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Anand gupta
9/21/2014 11:05:42 pm
sir in que no... 46 ...how to find the spring constant ....
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Om Patil
9/26/2014 10:00:27 pm
I am unable to understand q61 of exercise .PLEASE HELP ME.
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Harshit
9/29/2014 01:27:28 am
sir please tell me how to deal with the problems...i am not knowing how to start.......please help me..
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q
10/3/2014 11:25:45 pm
w
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abhishek
10/3/2014 11:27:44 pm
sir plz explain q 36 of hc verma collision
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saraswati
10/6/2014 01:31:11 am
sir can you explain how did you take sin52 x 0.96 A as x1 in 2 problem
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barsha
10/11/2014 03:44:53 pm
pls explain me the difference between the question 4 and 5
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In question 4 there are two discs placed one over another and in question 5 there is one disc of radius 2R from which a disc of radius R is cut out.
10/16/2014 06:06:20 am
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Rupak
10/14/2014 06:31:16 am
sir can you explain problem no. 44 a bit?
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shivam
11/17/2014 02:38:50 am
sir how we can identify where the centre of mass lying between the combination of system for example ques6 of objective1 in hc verma
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Shivam Anand
12/10/2014 11:25:08 pm
Sir, please help me out with q.no.-52 of chapter-9..
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saurabh
12/25/2014 02:00:27 pm
chapter 9 question 50 b
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viraj
1/6/2015 10:23:50 am
Sir can u tell me how do the trajectory equation in que no. 43 is plz explain it..
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tanvee
3/24/2015 12:58:31 pm
a sphere with velocity v strikes a wall moving towards it with velocity u. if the mass of walll is infinetly large then work done by the wall during perfect elastic collision will be ?
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Zlatan Ibrahimovic
4/21/2015 03:08:56 pm
The ans. for the third que is 22L/35 but the solution says 11L/35..?
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prabhat mishra
5/18/2015 08:37:48 pm
Sir,,please explain question no 60,61 from centre of mass
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sir question no 59 hcv
8/9/2015 05:27:13 am
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nikhil
9/27/2015 09:53:58 pm
u can ask me on my email id. i will send u the pic of soln
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saurabh
9/24/2015 09:16:28 pm
Hints for the q-13 and q-14 of h.c verma...conservation of linear momentum.....
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nikhil jha
9/27/2015 09:43:35 pm
ques 61.. why cant we use equation of a projectile(kinematics) to find the maximum height reached by the block taking our reference point as the top of wedge of mass M. then we can add the answer to the height h to get the final answer.
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sameer maurya
10/9/2015 05:19:34 am
sir i could understand Q..49 what is x in it. please explain me.
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bhoopesh
10/9/2015 07:26:49 am
Please explain friction 21 question exercise
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kanjal
10/22/2015 05:42:26 pm
can u please explain question 13 to me
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caersar
11/3/2015 10:18:31 pm
good initially but tons of misprints in many questions... horrible experience very frustrating.. sorry but take more care while publishing such important solutions.. so many solutions aren't clear due to wrong printing..students have a tough time deciphering what the solutions actually mean if you use the wrong terminologies like foe e.g.: u1 instead of v2, .6 in one line and 6 in the otheretc.. please look into this matter.
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vaishnavi
12/13/2015 06:07:28 am
aren't question 4 and 5 same?? then why is the answer different??
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dipssy
12/25/2015 09:37:29 pm
perfect solutions
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Riya
12/28/2015 08:30:24 am
Sir kindly explain me the prlb no.24 of hcv chapter- linear momentum
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innocent
3/8/2016 07:44:20 pm
A ring and a disc having the mass rolls without slipping with same linear velocity.if the kinetic energy of the ring is 8J.calculate the kinetic energy of the disc
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Manish moryani
3/19/2016 04:01:15 am
Four.
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sadik ali
7/15/2016 07:38:00 pm
sir plece solution for q2
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Agniva Roy
7/22/2016 08:02:12 am
Question no 52 of centre of mass impulse momentum.How can we say that acceleration will be F1-F2/m1+m2.How do we come to this conclusion?
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jones
8/23/2016 09:36:53 pm
i dont understand 11 ques of this chap
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rajan
9/2/2016 12:17:58 am
Sir, I facing problem in question for short answer in 9 CH of class11.
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Priyamvada
9/12/2016 11:26:18 pm
Can u explain me Q51 that how the equation 3 came???
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sweety priya
9/26/2016 09:30:25 am
Q.1of chap.centre of mass short answer type question
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Abhishek sawan
10/9/2016 08:02:04 am
Capeter 9 questions no 19 hc verma
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Toni
10/16/2016 05:51:55 pm
Ch 9 question no 7 of. HC Verma book
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Abhinav
6/13/2017 06:48:20 am
Hcv example no. 17 why the linear momentum is being conserved though there is external acc. 'g' acting downwards in vertical direction. please reply soon
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Utkarsh
10/20/2017 10:05:07 pm
Pls explain ques no 56 I am finding some errors in the soln
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Anupria
10/6/2018 12:10:52 am
Plz xplain centre of mass solved examples number 13 .how the mass of module is M/6
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