HC Verma Physics Part 1 Solutions for Chapter 22 Photometry

5/21/2012

Download HC Verma Solutions for HC Verma Physics Part 1 Solutions Chapter 22 Photometry solved by our expert teachers. We have curated solutions for all questions of chapter 23. You can download the Solution of HC Verma - Photometry and prepare for your upcoming competitive examinations.

Solution of HC Verma Concept of Physics -1- Chapter 22 Photometry

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6 Comments

preetam

10/25/2012 02:37:25 am

nt abl to slv exercise questn 4 of h.c.verma lesson 22

Admin

11/3/2012 03:29:53 pm

Dear preetam,
here we assume that the required Luminious flux of source be P Watt.
we know that for 1 Watt of 555nm luminious flux is 685. so for P watt, luminious flux is 685P.
thier ratio is equal to relative luminousity and is given by 0.6
from here we get luminious flux in terms of P which is equal to 120*685 because question is asking for 120 W. from there we have calculated P.

Admin

11/3/2012 03:41:34 pm

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Ashish

2/17/2013 04:16:13 am

What is difference & relation between charge &mass How does a body get it plz. send me ans.

theyatin

5/10/2013 03:29:05 am

dear,
charge is electric polarity of the body it may be postitve or negative.
mass is quantity to measure matter enclosed inside a particular body of certain volume.
mass is always constant. but charge may differ w .r.t. other charges present around it.

relation between mass and charges is only that there can be no charge on a mass less body. ..
there is no formula to relate them. . .

NIRBHAY KAUSHIK link

1/30/2015 09:47:28 pm

A mass m is supported by a massless string wound around a uniform hollow cylinder of mass mand radius R. If the string does not slip on the cylinder, with what acceleration will the mass fall on release. what is ans with step.

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