HC Verma Physics Part 1 Solutions for Chapter 2 Physics and Mathematics

5/21/2012

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Solution of HC Verma Concept of Physics -1- Chapter 2 Physics and Mathematics

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123 Comments

abhishek

10/29/2012 01:50:43 am

sir, i am not getting question no. 15 please help me

Admin - Answer

10/29/2012 10:07:27 pm

it's just a cross product.
here are two vectors A and B and we are doing their cross product.
you will study this topic in Vectors.

shrayam mitra

5/13/2016 09:49:51 pm

i am not getting q.3, of objective

Pragya

5/11/2018 10:36:57 pm

if a particle is moving with a uniform velocity then what is it's acceleration

aaa

5/1/2013 04:15:08 pm

please tell q12

theyatin

5/2/2013 07:25:33 pm

dear aaa,
In this Question we just have to put the values of the cosine in the given equation.
We know by the polygon law of vector that the if the starting and ending points of the vector is coinciding then the resultant vector is zero. If the resultant vector is zero then its resolving factors will also be zero i.e if we resolve it in the horizontal and vertical direction then also it will be zero.
Here the question is asking that if we resolve the resultant factor in the horizontal direction then prove by putting the values of cosine that the resultant is zero

aaa

5/9/2013 03:53:40 pm

how to put value of cosines in q12

RAVI RANJAN

6/27/2016 01:59:09 am

Bro x component means Px and y component Py here u have to take a3as a3 cos120 and sin60 and solve bro its similar to q5 almost same concept

aaa

5/13/2013 03:36:44 pm

please tell q12

theyatin

5/13/2013 04:10:52 pm

dear,
inregular hexagon the angle between two sides is always 120 or 2pi/3 so as external angle is pi/3

VAIBHAV

6/1/2014 08:10:28 pm

TO MAT KAR

Sam

8/16/2014 01:24:48 am

its a cross product
just arrange the i j k in a cyclic order(in columns)
i.e.-i,j,k,i(column wise) and then multiply it .....
in case of i leave the i-column and so on...

8/11/2016 09:14:57 am

Bro try it with determinant

Shivam

12/30/2016 01:20:57 am

Kulesh Kumar

8/6/2018 06:19:41 am

एक वस्तु तीसरे सेकंड 400 cmतथा 5वे सकेड 1200सेंटीमीटर की दूरी तय करता है यदि वस्तु एक समान रूप से त्वरित हो तो आखरी3 सेक... me Tay ki gayi duri gyat kare

Admin

11/3/2012 03:04:51 pm

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debasis

4/24/2013 07:31:30 pm

I really appriciate your free educating system now a days books are costly so your little effort can make big differeance. BEST OF LUCK

surya

11/14/2012 11:17:46 am

12q doubt

Admin

11/15/2012 12:15:19 am

we can see in the solution that all the six vectors are forming the Hexagon which is a closed loop. so the net resultant of Vector will be Zero.
Here we will resolve all the forces in the X and Y direction respectively.
Let us assume that the first vector is making an angle @ with the horizontal.
Now we have just resolved in the horizontal and vertical direction

akash

1/29/2013 03:51:15 pm

Not getting 12question

Admin

1/30/2013 09:34:05 am

Dear Akash,
In this Question we just have to put the values of the cosine in the given equation.
We know by the polygon law of vector that the if the starting and ending points of the vector is coinciding then the resultant vector is zero. If the resultant vector is zero then its resolving factors will also be zero i.e if we resolve it in the horizontal and vertical direction then also it will be zero.
Here the question is asking that if we resolve the resultant factor in the horizontal direction then prove by putting the values of cosine that the resultant is zero.

ashish

11/16/2015 04:48:48 pm

akash

1/29/2013 03:53:30 pm

8(a) ques.

Admin

1/30/2013 09:53:39 am

Dear Akash,
In this question please see the figure given in the solutions.
The Queen is going along the path GACE. Here please note that the triangle ABC and BCF are symmetric to eah other because the queen is rebounding and it will make equal angle with line CD or we can say that queen will move symmetric about the line CD.
this means that (angle BAC = angle BFC). also see that angle
BFC = DEC ...... corresponding angle
so, tan BAC = tan DEC
tan BAC = x/2
tan DEC = (2 - x) /4
puttin them equal, we can calculate x

so, in this part we have to find AC i.e distance between center and front edge which we have found by applying pythagoras theorem in traingle ABC.

srihitha

7/4/2015 03:11:21 pm

admin,
does rebound means make equal angles and come back? please clarify.

Shruti

12/27/2015 07:32:44 pm

basically the angles in this problem are equal as the collision can be considered to be completely elastic hence e=1 and both angles are equal........am i right admin???

akash

2/4/2013 07:26:47 pm

thank u

nikhil jain

2/19/2013 02:10:48 am

what is the difference b/w projection and component of vectors?

Admin

2/19/2013 07:33:29 pm

Dear Nikhil,
Projection and component are the same thing. Do not get confused with the term.

nikhil jain

2/20/2013 06:52:58 pm

ok..

nikhil jain

2/21/2013 08:42:15 pm

plz Sir, find the volume of the solid generated when ellipse revolves round it's major axis...??

Admin

2/22/2013 05:26:28 pm

The doubt solving service for HC verma has been disabled for few days. We are very happy with the faith the students have shown in our service. We are hiring more and more teachers and upgrading our features like audio video techniques to solve your doubts.

arsh

2/26/2013 10:50:00 pm

how resultant become 100 in 3rd sum

yash

4/16/2013 09:52:04 pm

sir i cannot understand q.no 3&5

theyatin

4/17/2013 09:03:30 pm

dear,
its just to explain angle of a vector along each coordinate axis. . .
first three values given in numerical is value of each vector along x coordinate axis.
similarly for Y axis.
as we know value of tan 45 is 1 thus have angle between Y an X

in Q5
three vectors are considered along two coordinate axis.
and then resultant is calculated. and thus calculating than alpha= Y component of each vector / X component of Each vector
we have angle.

abhi

5/7/2013 02:19:15 am

plz explain short type answers

theyatin

5/7/2013 06:41:23 pm

dear,
our technical team will shortly upload solutions of short answers too. . .

krupa

5/27/2013 03:45:40 pm

sir,i m not getting que no 18.please help me

theyatin

5/27/2013 06:07:56 pm

dear,
first two steps are easy to get as it is given.
as from right hand rule as you cross product between V and B implies resultant of this product is in opposite direction to E.
this implies that V and B are at 90'.
and from right hand rule clock wise E is along x axis direction,
B is along y axis.
V is along z axis.
i case the cross product between V and B would be positive then V would be along Y axis and B along z axis.

krupa

5/27/2013 07:03:52 pm

sir,will you plz explain me objective 2 que no. 2...

theyatin

5/28/2013 12:28:52 am

dear,
as A and B can be positive or negative both so you can not be certain about any of other options except b).
that is C<B or C<A

krupa

5/28/2013 02:38:10 am

sir,I m not able to understand concept of maxima and minima.....will u plz help me???

theyatin

5/28/2013 05:29:05 pm

dear,
maxima is the maximum value of a set under given function.
and minima is minimum value of a set under given function.

SURYA PRATAP SINGH

5/29/2013 11:47:34 pm

sir plz explain qn.5in obj 1

theyatin

5/30/2013 01:44:29 am

dear,in case of cross product the resultant is never opposite to any of the force
so the resultant can not be in downward as well as southward direction.
as well it can not be zero as its sin 90=1
so now from right hand rule draw North south west and east put your indes finger towards north thumb upwards and se where does middle finger directs you that is the answer.

niyati

5/30/2013 03:44:20 pm

sir please, can u explain me the 8th que of ch.2?

theyatin

5/30/2013 06:04:01 pm

dear,
a).AB=2/3
and BC= 2 that is half of the length of carom board
b)x=2/3
so DE=1-2/3
so CD=4 that is length of carom board.
c)AG=2 and GE=2 both are half of the length of carom board

Surya pratap

5/30/2013 05:22:30 pm

Sir plz tell me the rule of predicting the direction of cross product of two vectors.

theyatin

5/30/2013 06:08:43 pm

dear,
it is right hand rule
open your thumb and index finger at angle 90 to each other and open middle finger in such a way that it is 90 degree to index finger
now consider one of given value at thumb and other on index finger now where middle finger is pointing that is the direction of product of both values.
but in case given values are not perpendicular to each other, then the product is normal to the plane of the both values.

Surya pratap

5/30/2013 08:15:52 pm

thnks

surya pratap singh

5/30/2013 10:42:43 pm

sir plz tell me useful books of physics and math for IIT.

rayan

6/4/2013 03:02:31 pm

Q8 (carrom board)

theyatin

6/4/2013 06:35:31 pm

dear,
In this question please see the figure given in the solutions.
The Queen is going along the path GACE.
Here please note that the triangle ABC and BCF are symmetric to each other because the queen is rebounding and it will make equal angle with line CD or we can say that queen will move symmetric about the line CD.
this means that (angle BAC = angle BFC). also see that angle
BFC = DEC ...... corresponding angle
so, tan BAC = tan DEC
tan BAC = x/2
tan DEC = (2 - x) /4
putting them equal, we can calculate x

so, in this part we have to find AC i.e distance between center and front edge which we have found by applying Pythagoras theorem in triangle ABC.

vikash

6/19/2013 02:38:28 am

sir , i want to detail solution of q.no. 5 of objective 1 a*b cross product but a is upward and b is in x plane (north). so result should be perpendicular to both vector. but answer is west , why not east.

theyatin

6/21/2013 06:23:13 pm

dear,
in case of cross product the resultant is never opposite to any of the force
so the resultant can not be in downward as well as southward direction.
as well it can not be zero as its sin 90=1
so now from right hand rule draw North south west and east put your index finger towards north thumb upwards and see where does middle finger directs you that is the answer.

@25

7/4/2013 01:46:56 am

Dear sir,

can we solve 1,2 problem's in ijk form as it is more appropriate than parallelogram law

theyatin

7/5/2013 01:47:52 am

dear,
which problems??

jacobi

7/13/2013 04:23:37 pm

question for short answers no.3. , Does the phrase" direction of zero vector " have physical significance ? discuss in terms of velocity, force etc , kindly give me the answer to this question

theyatin

7/14/2013 02:57:12 am

dear,
there is no physical significance of zero vector.
The velocity vector of a stationary body is a zero vector. ( as ball thrown upward when comes back to the ground its velocity vector is zero vector.)
similarly force vector of a stationary body is a zero vector.

Abhay

4/22/2016 03:30:06 am

Biiiiiiig Thanks

jacobi

7/13/2013 04:28:39 pm

chapter2, questions for short ans no.5. can we have physical quantities having magnitude and direction which are not vectors ?

theyatin

7/14/2013 02:59:21 am

dear,
electric current has both mag. and dir. but do not follow vector addition hence it is not a vector quantity. so the answer is yes.

anil pathak

8/11/2013 04:27:33 pm

i want to ask you question no. 14 of chapter 2 short answer type please reply fast

theyatin

8/14/2013 07:08:12 pm

dear,
as vector is multiplied by scalar the magnitude of vector changes only so here in this case
B=-7.5i'+6j' = -3/2(5i'+4j') that is -3/2(A')
so B'=kA' that is B'/A' = -3/2

prateek verma

8/13/2013 03:07:36 pm

Q.1- is a vector necesaarily change if it is rotated through an angle.

theyatin

8/14/2013 07:06:02 pm

dear,
as vector has a direction when it changes its direction its magnitude would also change

ashok

8/15/2013 03:25:19 am

Does the phase " direction of zero vector " have physical significance ? Tell in terms of force, velocity etc

Q.2- Can you add 3 unit vectors to get a unit vector, give an EXAMPLE ? Does your answer change if 2 unit vectors are along the coordinate axes?

Q.3- Which of the two statement is more appropriate
(a) two forces are added using triangle rule because force is a vector quantity?
(b) force is a vector quantity because tu forces r added using triangle rule ?

heyatin

8/18/2013 04:56:06 am

dear,
Q2 yes we can add 3 vectors to add zero vector if all three vectors are along coordinate axes in 3 D

theyatin

8/18/2013 04:59:16 am

dear,
if 2 vectors are along coordinate axes then the third one must be along the third coordinate axis.

theyatin

8/18/2013 05:02:38 am

dear,
Q3
a) is more appropriate
because triangle rule doesnt determine whether some quantity is vector or not,
but if some quantity is vector it must be added by triangle rule.
hence a) is more appropriate.

sam

8/15/2013 03:29:41 am

Page number 28, question no. 9, 10

theyatin

8/18/2013 05:11:40 am

dear,
in Q9
as we need to calculate magnitude of displacement we need to find
underoot of sum of squares of coefficient of each unit vectors
that means,
(7^2+4^2+3^2)^1/2
where 7 is component of unit vector along x axis,
4 is component of unit vector along y axis,
and 3 is component of unit vector along z axis,
hence youhave xplaination for both parts.

theyatin

8/18/2013 05:14:41 am

dear,
Q10
if magnitude of some vector is given and that vector is multiplied by some number positive or negative
the resultant magnitude of vector is product of that number and its magnitude.

shagun

8/28/2013 07:54:04 pm

In Q14 how is ABsin@ perpendicular to A and B?
It is not given that angle is 90.

theyatin

8/30/2013 02:48:28 am

dear,
as the sin theta n^ is perpendicular to A and B
its n^unit vector that is perpendicular to A and B
that is what cross product mean

siddhartha kumar agarwal

11/16/2013 02:36:14 pm

kaha hai solution?

theyatin

11/17/2013 01:50:31 am

dear,
which solution. . .

rahul kumar

11/21/2013 06:11:29 pm

I don't understand torque, becouse this topic teached my teacher when i was not present there.

theyatin

11/22/2013 12:01:25 am

dear,
torque is force in angular motion
so
it is the tendency of a force to rotate an object about an axis
T= F X r

kalpesh

1/23/2014 03:01:53 am

Sir,I can't understand question no.8.please explain me.

Ping

4/10/2014 04:54:05 am

sir could you please explain the following question i.e. If vector A = 3i+4j and vector B = 5i+12j then what is the component of vector A along vector B.

Anmol

4/27/2014 05:13:15 am

sir/please explain the objective type I Q.no. 1 , 13 of chapter rest and motion: kinematics

Anmol

4/27/2014 05:39:35 am

Ch- kinematics objective II Q.no 9 sir how do we get know that particle came to rest 6 times from graph

ER.MIRJAIK

5/24/2014 02:14:15 pm

in Q9
as we need to calculate magnitude of displacement we need to find
underoot of sum of squares of coefficient of each unit vectors
that means,
(7^2+4^2+3^2)^1/2
where 7 is component of unit vector along x axis,
4 is component of unit vector along y axis,
and 3 is component of unit vector along z axis,
hence youhave xplaination for both parts.

Anmol

4/27/2014 05:47:13 am

ch kinematics objective II q.no. 10 plz explain

ER.MIRJAIK

5/24/2014 02:12:54 pm

Q10
if magnitude of some vector is given and that vector is multiplied by some number positive or negative
the resultant magnitude of vector is product of that number and its magnitude.

shreya

5/15/2014 09:25:39 pm

i am not able to get question no. 14

bcoz i think avector x bvector=abcos@ inspite of ab sin@

ER.MIRJAIK

5/24/2014 02:08:54 pm

dear,
as vector is multiplied by scalar the magnitude of vector changes only so here in this case
B=-7.5i'+6j' = -3/2(5i'+4j') that is -3/2(A')
so B'=kA' that is B'/A' = -3/2

ER.MIRJAIK

5/24/2014 02:10:18 pm

as the sin theta n^ is perpendicular to A and B
its n^unit vector that is perpendicular to A and B
that is what cross product mean

shreya

5/21/2014 08:44:36 pm

sir q.16 plz...

DIVYA

5/22/2014 02:03:49 am

CH 2 EXERCISE QUESTION NO. 19 PLZ SOLVE

ER.MIRJAIK

6/2/2014 12:39:14 am

zakra

5/23/2014 01:21:14 am

plz give the answers of chapter 2 of part 1

mirjaik

6/2/2014 12:34:51 am

it will be uploded soon

rakesh

6/12/2014 01:03:43 pm

Sir, can u give solution of Rd sharma class 11

Shubhi

6/16/2014 09:00:24 pm

Does the resultant of two or more vectors give the displacement of a particle if the vectors represent the path followed by the particle ?

Admin

6/22/2014 01:40:31 pm

Dear Students,
Our Teacher is unavailable for few days. We are sorry for this inconvenience. Our teacher will give your answers soon.

DHARMIT

7/24/2014 10:24:59 pm

THANK YOU FOR PROVIDING THIS FREE EDUCATION .

pryanshu

8/8/2014 05:06:25 pm

prince

8/22/2014 02:43:06 am

sir. parabola me doubt hay

saddam husain

8/26/2014 03:44:41 am

How displacement depend upon time give me a easy example

Niranjan

9/3/2014 02:57:51 pm

Amar

9/11/2014 02:54:38 am

sir,how to solve q no5

SANJAY

9/13/2014 07:30:04 pm

A spy report about a suspected car reads as follows. The car moved 2kms towards east, made a pependicular left turn, ran for 500m, made a perpendicular right turn, ran for 4km and stopped. Find the displacement of the car.

ketan chawade link

9/17/2014 04:54:12 pm

sir; i m not getting que. no. 08

Manish.Chandrashekar

10/27/2014 04:10:34 am

can you please explain 3rd question how did resultant become 100??

Gautham link

5/10/2015 12:45:16 am

Sir,
There appears to be subtle mistakes in the given solutions,for questions 21 and 23.
Looking for a genuine solution.

Jay

6/14/2015 05:54:19 pm

Sir can u help me in getting que. No. 17

sanchit

7/4/2015 12:47:38 am

in 12th question how this eq came?
that pie/2+pie/3 ....and all
please explain?

shelly

9/26/2015 09:46:43 pm

question no.22 doubt

Sudarshan

12/14/2015 05:14:49 pm

In 23 c, how does 2* e^-0.31/0.30 become 5.8/3e?

ananta kumar nanda

1/4/2016 09:17:05 am

SARTHAK link

1/15/2016 07:19:04 am

let vector A= 5i-4j and vector B=-7.5i +6j.Do we have B=KA?Can we say that B/A =K

Sawako

3/29/2016 10:06:42 am

I could not understand example 2.1
Please help me understand why we get such answers

Abhay

4/22/2016 04:43:14 am

Can you please explain 7th short answer about adding 2 vectors in different dimensions

jyotsna

5/1/2016 07:44:06 am

Plz tell q12

rishu

5/12/2016 02:11:52 am

I am not getting Q.22

Rohan

7/3/2016 04:34:27 am

I need short type answers for chapter 2..Please

Amit

7/6/2016 08:12:48 am

Chapter 2 Q.2

Chapter 2 Q..2

Gaurav Shrivastava

9/1/2016 07:33:02 am

Sir ,please provide ans to short answer questions and objectives...with explanations please,please Sir ....I will be very thankful to you...please

Nemesis link

12/17/2016 11:42:58 pm

Bhoomika link

4/21/2018 07:31:18 am

Please explain example no.2.1 from concepts of physics 1

palak

9/23/2018 04:22:06 am

please help me with example 2.2 (a) part .

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Solution of HC Verma Concept of Physics -1- Chapter 2 Physics and Mathematics

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