HC Verma Physics Part 1 Solutions for Chapter 16 Sound Waves

5/21/2012

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Solution of HC Verma Concept of Physics -1- Chapter 16 Sound Waves

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46 Comments

admin

11/3/2012 03:44:54 pm

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mohan

8/14/2014 12:44:26 am

Part 1 of H C Verma. Sound waves,In Q83-b, frequency due to Doppler effect is given as 2000 Hz,where as in Q86-b and 86-d different frequencies are given even though in both cases source is moving perpendicular.Is there transverse Doppler effect ?

Suyash

2/4/2013 08:25:35 pm

A cylindrical tube, open at both ends, has a fundamental frequency F in air. The tube is dipped vertically into water such that half of its length is inside water. The fundamental frequency of air column is now
3F/4
F
F/2
2F

Admin

2/5/2013 06:54:22 pm

Dear Suyush,
In this question first we will calculate the fundamental frequency of the cylindrical tube.
Let there is a node at both the ends of the cylindrical tube. Then
distance between two nodes = λ/2 = l
or λ = 2l
where l = length of the cylindrical tube
the natural frequency v = speed of sound / λ = speed of sound / (2l)
Now there is water at half the distance of the tube. This means that the anti node is forming at the water surface.
so, distance between node and anti node = λ/4
length of tube covered = l/2
so, λ/4 = l/2
λ = 2l

frequency = speed of sound / λ = speed of sound = 2l
again we are getting the same frequency. This means that the frequency remains same.

shivam

4/26/2014 05:28:24 pm

kashaf

10/22/2014 07:46:42 pm

F ... frequency is a rigid factor

ayush

2/18/2013 07:18:34 pm

plz explain ques.31(hcv)

sam

4/18/2013 05:11:32 pm

how is that when loudness is 120 dB , the intensity is 1 W/(m^2) ?
(ques. 21)

theyatin

4/18/2013 10:48:38 pm

dear,
dB= 10 log10 (I/Io)
according to this intensity I is approx 1 W/m^2

kashaf

10/22/2014 07:51:40 pm

how ??? i0 is taken as 10^-12 for reference

kashaf

10/22/2014 07:50:32 pm

suno yaar ... dB=10log10(i/i0) hai ?
120=10log10(i/i0)
120=120log10(i) (dB=120 given
i0=10^-12 2/m^2 reference ..... refer to HCV theory)
10=i
ab i ko 10 rakh kar solve kar answer aa jaye ga .... galat solve kare hai ye log yaar

aman sangal

5/6/2013 07:34:44 pm

you haven't solved question 33. question 34 is marked as 33 in your answer.

theyatin

5/6/2013 08:53:37 pm

dear,
thank you for pointing out mistake. . .

Arindam Nandi

1/25/2014 11:40:41 pm

Sir, in Q.24 why is wave length/4=2.5?
Shouldn't it be =5.0 cm. since in Quincke's apparatus, when the movable part is pulled out, the total increase in path length is 5.0cm.

kashaf

10/22/2014 07:53:39 pm

distance b/w consecutive node and antinode lamda/4 hi hoti hai

shivani sharma

2/6/2014 12:56:40 am

sir,in Q.-6,why it is written that sound waves spread in all directions if wavelength of sound is much larger than the diameter of the speaker?

theyatin

2/10/2014 02:17:59 am

dear,
it is due to diffraction.
just like light coming from small aperture diffracts to spread.

shivani sharma

2/6/2014 06:00:24 am

sir can we say that in resonance there are no beats produced?

theyatin

2/10/2014 02:15:38 am

dear,
resonance is continuous sound
beat is high amplitude and low frequency sound clip.

Rohan

2/13/2014 02:19:04 pm

What do we mean by resonance condition in all these cases ??

theyatin link

2/13/2014 11:38:26 pm

dear,
i cant understand what you are asking?

i am providing a link to study more about resonance.

rahul

2/21/2014 12:52:19 am

sound wave question 87

theyatin

2/25/2014 02:37:06 pm

dear,
87. Let the distance between the source and the observer is ‘x’ (initially)
So, time taken for the first pulse to reach the observer is t1 = x/v
and the second pulse starts after T (where, T = 1/v)
and it should travel a distance [x-1/2at^2]
(S=ut+1/2at^2 => ut=S-1/2at^2)
[t=(S-1/2at^2)/ u]
now t2=T+t

zhenith gour

2/25/2014 03:20:13 am

if the pipe open at both ends resonates to a frequency n1 and a pipe closed at one end resonates to a frequency n2, if they joint to make a pipe closed at one end, then the fundamental frequency will be
n1n2/ 2 n2 + n1
2 n2 n1/ 2 n2 + n1
2 n2 n1 / n1 + n2
n2 + 2n1/ n1 n2

plz sir, reply

2/26/2014 03:00:07 am

when will i hav my ans sir?

3/8/2014 03:25:31 am

Alok Kumar Sharma

3/11/2014 11:33:47 pm

I Think the ans is the first option n1n2/2 n2 + n1, let me explain:-
let "L1" be the length of the pipe open at both ends and "L2" be the length of the pipe closed at one end. and let "v" be the speed of wave in the medium
for the pipe open at both ends
fundamental frequency = n1 = v/2 L1
=> L1=v/2 n1
for the pipe closed at one end
fundamental frequency =n2 = v/4 L2
=> L2=v/4 n2

now, total length of the pipe = L1+L2
=> (v/2 n1) +(v/4 n2) let this be equal to L
now, as the combined pipe is also a pipe closed at one end, therefore the fundamental frequency of this pipe is = v/4L
putting the value of L in the above expression, we get the answer as, (n1*n2) / (2 n2 + n1)

Rahul gaydhane

3/4/2014 09:49:59 pm

R.7.

Manshi

3/15/2014 06:21:36 pm

not getting Q.no 21 of chapter 16 i.e of sound waves. can u help me out?

theyatin

3/17/2014 01:59:00 pm

dear,
intensity=power/ area
power is 2W and area is of sphere

zhenith gour

4/24/2014 08:06:49 pm

Thanx sir, u r great

Vismay

6/11/2014 10:27:17 pm

Sir in que 32 why it is mentioned that S1S2=S2S3

Vismay

6/11/2014 10:42:40 pm

And sir why there is no information given about frequency or wavelength ...do there is any derivation from the statement given about distances b/w sources for frequency to be equal...

sai

7/2/2014 12:25:40 pm

67 th question calculation is wrong

mahesh

8/28/2014 12:21:57 pm

33 question isn't explained and skipped to 34
I request a solution to the 33Q

12/11/2014 02:07:47 am

will you pllz upload ans of the latest edition...i guess the ans given r for a older edition n doesnt match with my book

suyash

3/6/2015 10:11:00 pm

ques 28

shashi

4/25/2015 03:47:52 pm

In the. 58th question why did it change to Tb / Ta

gaziya

10/18/2015 01:39:03 am

what is the unit of force

mahesh

1/16/2016 08:17:35 am

In que 43 the rod acts as open organ pipe but it is clamped in middle so even harmonic should be skipped

mahesh

1/16/2016 08:21:44 am

Sir please reply at earliest

Ryan link

3/17/2016 09:00:55 pm

Sir/Madam,
Could you explain the calculus part of Question 14 of Sound Waves?

Thanks

Sneha

11/26/2016 08:14:03 pm

Please can u explain ques 83 to me

sakshi

1/11/2017 08:14:57 pm

Ques 7th part c

Prashant Patil

2/6/2017 07:50:36 am

Are plz explain H.C.V ch no.16 question no 3

mrityunjoy gope

4/20/2017 12:42:24 am

please explain Q15 NO

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